Vertical velocity at maximum height in projectile motion

Practice question

Question

A ball is thrown at 40m/s at 30∘. What is its vertical velocity at the maximum height? (Take g\=10m/s2)

Options

Choose one · Correct answer highlighted

20 m/s 10 m/s 40 m/s 0 m/s Correct

Explanation

Velocity v=v₀+at. Starting from rest, v=at. With a=(ax i+ay j), magnitude |v|=t√(ax²+ay²) per NCERT vector addition. Substituting ax, ay, t gives |v| equal to 0 m/s. Hence option D is correct.

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