Practice question
Question
A ball is thrown at 22m/s at 60∘. What is its vertical velocity at t\=1.5s? (Take g\=10m/s2,sin60∘\=0.866)
Explanation
Vertical velocity vy=v0sinθ0−gt. As per NCERT Chapter 3, equations v=u+at, s=ut+½at², v²=u²+2as describe uniformly accelerated motion. Applying correct signs and units gives 5 m/s as the result, so option A is correct.