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#Kinematics

197 public questions tagged with this topic.

Laws of Motion and Energy Conservation

A 3kg object is dropped from 17m. What is its speed just before hitting the ground? (Take g\=10m/s2)

Potential energy V=mgh=3×10×17=510J. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 18 m/s. This satisfies dimensional consistency and physical conditions given, so option A is scientifically correct.

Ref: NCERT Class 11 Physics > Chapter 6: Work, Energy and Power > Topic: Laws of Motion and Energy Conservation

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Work, Energy and Power - Work-Energy Theorem

A 0.2kg ball is dropped from 12m. What is its speed just before hitting the ground? (Take g\=10m/s2)

Potential energy V=mgh=0.2×10×12=24J. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 14 m/s. This satisfies dimensional consistency and physical conditions given, so option A is scientifically correct.

Ref: NCERT Class 11 Physics > Chapter 6: Work, Energy and Power > Topic: Work, Energy and Power - Work-Energy Theorem

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Relative Motion and Plane Motion

What is the primary factor affecting the time of flight of a projectile launched from level ground?

Projectile motion splits into horizontal uniform and vertical accelerated motion per NCERT Chapter 4. Range R=u²sin2θ/g and max height H=u²sin²θ/2g. Using given u, θ, g, calculation yields Horizontal velocity. Hence option A satisfies projectile formulas.

Ref: NCERT Class 11 Physics > Chapter 4: Motion in a Plane > Topic: Relative Motion and Plane Motion

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Relative Motion and Plane Motion

For a projectile launched at an angle, what is true about the horizontal and vertical motions?

Projectile motion splits into horizontal uniform and vertical accelerated motion per NCERT Chapter 4. Range R=u²sin2θ/g and max height H=u²sin²θ/2g. Using given u, θ, g, calculation yields They are independent. Hence option C satisfies projectile formulas.

Ref: NCERT Class 11 Physics > Chapter 4: Motion in a Plane > Topic: Relative Motion and Plane Motion

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Relative Motion and Plane Motion

A projectile is launched at 34m/s at 60∘. What is its horizontal range? (Take g\=9.8m/s2,sin⁡120∘\=0.866)

Projectile motion splits into horizontal uniform and vertical accelerated motion per NCERT Chapter 4. Range R=u²sin2θ/g and max height H=u²sin²θ/2g. Using given u, θ, g, calculation yields 92.5 m. Hence option A satisfies projectile formulas.

Ref: NCERT Class 11 Physics > Chapter 4: Motion in a Plane > Topic: Relative Motion and Plane Motion

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Relative Motion and Plane Motion

A projectile is launched at 25m/s at 37∘. What is its vertical velocity at t\=1s? (Take g\=10m/s2,sin⁡37∘\=0.6)

Projectile motion splits into horizontal uniform and vertical accelerated motion per NCERT Chapter 4. Range R=u²sin2θ/g and max height H=u²sin²θ/2g. Using given u, θ, g, calculation yields 5 m/s. Hence option C satisfies projectile formulas.

Ref: NCERT Class 11 Physics > Chapter 4: Motion in a Plane > Topic: Relative Motion and Plane Motion

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Projectile and Circular Motion Basics

What is the primary factor determining the range of a projectile launched from level ground?

Projectile motion splits into horizontal uniform and vertical accelerated motion per NCERT Chapter 4. Range R=u²sin2θ/g and max height H=u²sin²θ/2g. Using given u, θ, g, calculation yields Launch angle and initial speed. Hence option B satisfies projectile formulas.

Ref: NCERT Class 11 Physics > Chapter 4: Motion in a Plane > Topic: Projectile and Circular Motion Basics

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Projectile and Circular Motion Basics

A projectile is launched at 40m/s at 37∘. What is its speed at maximum height? (Take g\=10m/s2,cos⁡37∘\=0.8)

Projectile motion splits into horizontal uniform and vertical accelerated motion per NCERT Chapter 4. Range R=u²sin2θ/g and max height H=u²sin²θ/2g. Using given u, θ, g, calculation yields 32 m/s. Hence option D satisfies projectile formulas.

Ref: NCERT Class 11 Physics > Chapter 4: Motion in a Plane > Topic: Projectile and Circular Motion Basics

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Projectile and Circular Motion Basics

A projectile is launched at 24m/s at 60∘ to the horizontal. What is its time of flight? (Take g\=9.6m/s2,sin⁡60∘\=0.866)

Projectile motion splits into horizontal uniform and vertical accelerated motion per NCERT Chapter 4. Range R=u²sin2θ/g and max height H=u²sin²θ/2g. Using given u, θ, g, calculation yields 2 v. Hence option A satisfies projectile formulas.

Ref: NCERT Class 11 Physics > Chapter 4: Motion in a Plane > Topic: Projectile and Circular Motion Basics

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