Practice question

Given: A train accelerates uniformly from 15 m/s to 35 m/s in 8 s . What is the distance covered? These values define the system as per NCERT data. Formula: Find a = v - v_0/t = 35 - 15/8 = 2.5 m/s². This is the standard NCERT relation for this phenomenon. Substitution & Calculation: Use x = v_0 t + 1/2 a t² = 15 · 8 + 1/2 · 2.5 · (8)² = 120 + 80 = 200 m . The distance covered is 200 m . Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kg⁻¹ K⁻¹, m/s², 10⁻⁵ are properly used as per NCERT.