The formula of the deep red liquid formed on heating potassium dischromate with KCI in conc. H₂SO₄ is:
CrO₂Cl₂ correct as per chemistry principle.
Ref: NCERT Chemistry Class XI and XII
#KCl
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When I₂ is passed through KCL, KF and KBr solutions
None of the above correct as per chemistry principle.
Ref: NCERT Chemistry Class XII — Solutions
If KCl is doped with 10⁻⁴ mol% of SrCl₂, then what is the concentration of cation vacancies?
KCl doped SrCl₂ cation vacancy Sr²⁺ replaces 2 K⁺ 6.02×10¹⁷ vacancies.
Ref: NCERT Chemistry Class XII — The Solid State
How many grams of K₂CO₃ are required to produce 13.8 g of KCl with excess HCl? (Molar masses: K₂CO₃ = 138 g/mol, KCl = 7
Reaction: K₂CO₃ + 2HCl → 2KCl + CO₂ + H₂O. Moles of KCl ≈ 0.1852 mol. 2 mol KCl from 1 mol K₂CO₃; 0.1852 mol from 0.0926 mol. Mass ≈ 12.78 g.
Ref: NCERT Class 11 Chemistry > Chapter 1: Some Basic Concepts of Chemistry > Topic: Reactions in Solutions and Mass Percentage and Numericals
How many grams of KOH are required to produce 7.45 g of KCl with excess HCl? (Molar masses: KOH = 56 g/mol, KCl = 74.5 g
Reaction: KOH + HCl → KCl + H₂O. Moles of KCl = 7.45/74.5 = 0.1 mol. 1 mol KCl from 1 mol KOH; mass = 0.1 × 56 = 5.6 g.
Ref: NCERT Class 11 Chemistry > Chapter 1: Some Basic Concepts of Chemistry > Topic: Mole Concept and Molar Masses and Percentage Composition
