Practice question
Question
How many grams of K₂CO₃ are required to produce 13.8 g of KCl with excess HCl? (Molar masses: K₂CO₃ = 138 g/mol, KCl = 74.5 g/mol)
Explanation
Reaction: K₂CO₃ + 2HCl → 2KCl + CO₂ + H₂O. Moles of KCl ≈ 0.1852 mol. 2 mol KCl from 1 mol K₂CO₃; 0.1852 mol from 0.0926 mol. Mass ≈ 12.78 g.
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