Practice question
Question
How many grams of KOH are required to produce 7.45 g of KCl with excess HCl? (Molar masses: KOH = 56 g/mol, KCl = 74.5 g/mol)
Explanation
Reaction: KOH + HCl → KCl + H₂O. Moles of KCl = 7.45/74.5 = 0.1 mol. 1 mol KCl from 1 mol KOH; mass = 0.1 × 56 = 5.6 g.
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