How many grams of KOH are required to produce 7.45 g of KCl with excess HCl? (Molar masses: KOH = 56 g/mol, KCl = 74.5 g
Reaction: KOH + HCl → KCl + H₂O. Moles of KCl = 7.45/74.5 = 0.1 mol. 1 mol KCl from 1 mol KOH; mass = 0.1 × 56 = 5.6 g.
Ref: NCERT Class 11 Chemistry > Chapter 1: Some Basic Concepts of Chemistry > Topic: Mole Concept and Molar Masses and Percentage Composition
