A projectile is launched at 36m/s at 37∘. What is its horizontal range? (Take g\=12m/s2,sin74∘\=0.96)
Projectile motion splits into horizontal uniform and vertical accelerated motion per NCERT Chapter 4. Range R=u²sin2θ/g and max height H=u²sin²θ/2g. Using given u, θ, g, calculation yields 103.7 m. Hence option A satisfies projectile formulas.
Ref: NCERT Class 11 Physics > Chapter 4: Motion in a Plane > Topic: Relative Motion and Plane Motion