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Practice question

MCQ

Question

A ball is thrown horizontally at 15m/s from a height of 98m. What is its horizontal range? (Take g\=9.8m/s2)

Options

Choose one · Correct answer highlighted

Explanation

Time to fall: h=12gt2⇒98=12×9.8×t2⇒98=4.9t2⇒t2=20⇒t=20≈4.47s. As per NCERT Chapter 3, equations v=u+at, s=ut+½at², v²=u²+2as describe uniformly accelerated motion. Applying correct signs and units gives 60 m as the result, so option A is correct.

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