Practice question
Question
In projectile motion, what is the condition for achieving maximum horizontal range on level ground?
Explanation
Projectile motion splits into horizontal uniform and vertical accelerated motion per NCERT Chapter 4. Range R=u²sin2θ/g and max height H=u²sin²θ/2g. Using given u, θ, g, calculation yields Launch angle of 45°. Hence option D satisfies projectile formulas.