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#car motion

6 public questions tagged with this topic.

Acceleration and Velocity Analysis

A car moves north at 12m/s while a wind blows east at 5m/s. What is the magnitude of the car’s velocity relative to the

Velocity components: vx=5m/s,vy=12m/s. As per NCERT Chapter 3, equations v=u+at, s=ut+½at², v²=u²+2as describe uniformly accelerated motion. Applying correct signs and units gives 13 m/s as the result, so option B is correct.

Ref: NCERT Class 11 Physics > Chapter 3: Motion in a Straight Line > Topic: Acceleration and Velocity Analysis - Part 8

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Equations of Motion and Problem Solving

A car accelerates from 5m/s at 2m/s2 for 6s, then moves at constant speed for 3s. What is the average speed over this ti

Phase 1: v=5+2⋅6=17m/s, x1=5⋅6+12⋅2⋅(6)2=30+36=66m. As per NCERT Chapter 3, equations v=u+at, s=ut+½at², v²=u²+2as describe uniformly accelerated motion. Applying correct signs and units gives 13 m/s as the result, so option C is correct.

Ref: NCERT Class 11 Physics > Chapter 3: Motion in a Straight Line > Topic: Equations of Motion and Problem Solving

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Equations of Motion and Problem Solving

A car accelerates from rest at 3m/s2 for 4s, then moves at constant speed for 6s, and decelerates to rest at 2m/s2. What

Phase 1: v=3⋅4=12m/s, x1=12⋅3⋅(4)2=24m. As per NCERT Chapter 3, equations v=u+at, s=ut+½at², v²=u²+2as describe uniformly accelerated motion. Applying correct signs and units gives 132 m as the result, so option C is correct.

Ref: NCERT Class 11 Physics > Chapter 3: Motion in a Straight Line > Topic: Equations of Motion and Problem Solving

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Distance, Displacement and Velocity-Time Relations

A car moves at 15m/s and decelerates at 3m/s2 for 3s, then accelerates at 2m/s2 for 6s. What is the net displacement?

Phase 1: v=15−3⋅3=6m/s, x1=15⋅3−12⋅3⋅(3)2=45−13.5=31.5m. As per NCERT Chapter 3, equations v=u+at, s=ut+½at², v²=u²+2as describe uniformly accelerated motion. Applying correct signs and units gives 100 m as the result, so option A is correct.

Ref: NCERT Class 11 Physics > Chapter 3: Motion in a Straight Line > Topic: Distance, Displacement and Velocity-Time Relations

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Distance, Displacement and Velocity-Time Relations

A car accelerates from rest at 5m/s2 for 4s, then decelerates at 2.5m/s2 until its speed is 10m/s. What is the total dis

Phase 1: v=5⋅4=20m/s, x1=12⋅5⋅(4)2=40m. As per NCERT Chapter 3, equations v=u+at, s=ut+½at², v²=u²+2as describe uniformly accelerated motion. Applying correct signs and units gives 95 m as the result, so option A is correct.

Ref: NCERT Class 11 Physics > Chapter 3: Motion in a Straight Line > Topic: Distance, Displacement and Velocity-Time Relations

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Distance, Displacement and Velocity-Time Relations

A car moving at 35m/s decelerates uniformly to rest over 87.5m. What is the deceleration?

Use v2=v02+2ax. Here, v=0, v0=35m/s, x=87.5m. As per NCERT Chapter 3, equations v=u+at, s=ut+½at², v²=u²+2as describe uniformly accelerated motion. Applying correct signs and units gives 7 m/s² as the result, so option B is correct.

Ref: NCERT Class 11 Physics > Chapter 3: Motion in a Straight Line > Topic: Distance, Displacement and Velocity-Time Relations

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