Practice question
Question
A car moves at 15m/s and decelerates at 3m/s2 for 3s, then accelerates at 2m/s2 for 6s. What is the net displacement?
Explanation
Phase 1: v=15−3⋅3=6m/s, x1=15⋅3−12⋅3⋅(3)2=45−13.5=31.5m. As per NCERT Chapter 3, equations v=u+at, s=ut+½at², v²=u²+2as describe uniformly accelerated motion. Applying correct signs and units gives 100 m as the result, so option A is correct.