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#deceleration

41 public questions tagged with this topic.

Equations of Motion and Problem Solving

A train moving at 90km/h accelerates at 0.8m/s2 for 15s, then decelerates at 2.5m/s2 to rest. What is the total distance

Speed: 90km/h=25m/s. As per NCERT Chapter 3, equations v=u+at, s=ut+½at², v²=u²+2as describe uniformly accelerated motion. Applying correct signs and units gives 730 m as the result, so option A is correct.

Ref: NCERT Class 11 Physics > Chapter 3: Motion in a Straight Line > Topic: Equations of Motion and Problem Solving

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Equations of Motion and Problem Solving

A parachutist falls freely for 2.5s before opening the parachute, then decelerates at 4m/s2 to hit the ground at 5m/s. W

Free fall: v=gt=10⋅2.5=25m/s. As per NCERT Chapter 3, equations v=u+at, s=ut+½at², v²=u²+2as describe uniformly accelerated motion. Applying correct signs and units gives 6 s as the result, so option A is correct.

Ref: NCERT Class 11 Physics > Chapter 3: Motion in a Straight Line > Topic: Equations of Motion and Problem Solving

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Equations of Motion and Problem Solving

A car accelerates from rest at 3m/s2 for 4s, then moves at constant speed for 6s, and decelerates to rest at 2m/s2. What

Phase 1: v=3⋅4=12m/s, x1=12⋅3⋅(4)2=24m. As per NCERT Chapter 3, equations v=u+at, s=ut+½at², v²=u²+2as describe uniformly accelerated motion. Applying correct signs and units gives 132 m as the result, so option C is correct.

Ref: NCERT Class 11 Physics > Chapter 3: Motion in a Straight Line > Topic: Equations of Motion and Problem Solving

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Uniform Acceleration and Graphical Analysis

A car accelerates from rest at 2.5m/s2 until it reaches 25m/s, then immediately decelerates at 5m/s2 to rest. What is th

Acceleration: t1=252.5=10s. As per NCERT Chapter 3, equations v=u+at, s=ut+½at², v²=u²+2as describe uniformly accelerated motion. Applying correct signs and units gives 12 s as the result, so option A is correct.

Ref: NCERT Class 11 Physics > Chapter 3: Motion in a Straight Line > Topic: Uniform Acceleration and Graphical Analysis

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Uniform Acceleration and Graphical Analysis

A car decelerates uniformly from 16m/s to rest over a distance of 32m. What is the deceleration?

Use v2=v02+2ax. Here, v=0, v0=16m/s, x=32m. As per NCERT Chapter 3, equations v=u+at, s=ut+½at², v²=u²+2as describe uniformly accelerated motion. Applying correct signs and units gives 4 m/s² as the result, so option B is correct.

Ref: NCERT Class 11 Physics > Chapter 3: Motion in a Straight Line > Topic: Uniform Acceleration and Graphical Analysis

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Uniform Acceleration and Graphical Analysis

A vehicle moving at 30m/s decelerates uniformly to rest in 100m. What is the time taken to stop?

Use v2=v02+2ax to find a: 0=(30)2+2a(100)⇒0=900+200a⇒a=−4.5m/s2. As per NCERT Chapter 3, equations v=u+at, s=ut+½at², v²=u²+2as describe uniformly accelerated motion. Applying correct signs and units gives 6 s as the result, so option B is correct.

Ref: NCERT Class 11 Physics > Chapter 3: Motion in a Straight Line > Topic: Uniform Acceleration and Graphical Analysis

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Uniform Acceleration and Graphical Analysis

A car moving at 50m/s decelerates uniformly to rest over 125m. What is the time taken to stop?

Use v2=v02+2ax to find a: 0=(50)2+2a(125)⇒0=2500+250a⇒a=−10m/s2. As per NCERT Chapter 3, equations v=u+at, s=ut+½at², v²=u²+2as describe uniformly accelerated motion. Applying correct signs and units gives 5 s as the result, so option D is correct.

Ref: NCERT Class 11 Physics > Chapter 3: Motion in a Straight Line > Topic: Uniform Acceleration and Graphical Analysis

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Motion in a Straight Line - Advanced Problems

A truck moving at 90km/h applies brakes and stops after 12s. If the deceleration triples after 8s, what is the total dis

Speed: 90km/h=25m/s. As per NCERT Chapter 3, equations v=u+at, s=ut+½at², v²=u²+2as describe uniformly accelerated motion. Applying correct signs and units gives 190 m as the result, so option A is correct.

Ref: NCERT Class 11 Physics > Chapter 3: Motion in a Straight Line > Topic: Motion in a Straight Line - Advanced Problems

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