Practice question
Question
A car accelerates from rest at 3m/s2 for 4s, then moves at constant speed for 6s, and decelerates to rest at 2m/s2. What is the total distance?
Explanation
Phase 1: v=3⋅4=12m/s, x1=12⋅3⋅(4)2=24m. As per NCERT Chapter 3, equations v=u+at, s=ut+½at², v²=u²+2as describe uniformly accelerated motion. Applying correct signs and units gives 132 m as the result, so option C is correct.