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Velocity v=v₀+at. Starting from rest, v=at. With a=(ax i+ay j), magnitude |v|=t√(ax²+ay²) per NCERT vector addition. Substituting ax, ay, t gives |v| equal to Tangential to the path. Hence option A is correct.
Ref: NCERT Class 11 Physics > Chapter 4: Motion in a Plane > Topic: Projectile and Circular Motion Basics
Velocity v=v₀+at. Starting from rest, v=at. With a=(ax i+ay j), magnitude |v|=t√(ax²+ay²) per NCERT vector addition. Substituting ax, ay, t gives |v| equal to Centripetal force. Hence option D is correct.
Ref: NCERT Class 11 Physics > Chapter 4: Motion in a Plane > Topic: Projectile and Circular Motion Basics
The acceleration vector in motion with constant acceleration remains constant in both magnitude and direction. This allows the motion to be analyzed as two independent one-dimensional motions along perpendicular axes. As per NCERT Class 11 Chapter 2, dimensional analysis checks correctness and SI units define base and derived quantities. This principle confirms that It changes magnitude is correct because its dimensions and unit match the physical quantity asked.
Ref: NCERT Class 11 Physics > Chapter 2: Units and Measurements > Topic: SI Units and Dimensional Formulae
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