Skip to content
Login Register

#Acceleration

84 public questions tagged with this topic.

PHYSICS

A 5 kg mass on a horizontal surface ( μ_k = 0.4 ) is pulled by a 3 kg mass over a pulley with a 10 N force aiding the 5

Given: A 5 kg mass on a horizontal surface ( μ_k = 0.4 ) is pulled by a 3 kg mass over a pulley with a 10 N force aiding the 5 kg mass. What is the acceleration? (Take g = 10 m/s² ) These values define the system as per NCERT data. Formula: For 3 kg : 3g - T = 3a Rightarrow 30 - T = 3a. This is standard NCERT relation. Substitution & Calculation: For 5 kg : T + 10 - f_k = 5a, f_k = 0.4 × 5 × 10 = 20 N . T + 10 - 20 = 5a Rightarrow T - 10 = 5a . Solve: 30 - T = 3a, T - 10 = 5a Rightarrow 30 - (5a + 10) = 3a . 30 - 10 - 5a = 3a Rightarrow 20 = 8a Rightarrow a = 2.5 m/s² . Result: The computed value matches expected outcome and confirms correct choice as per NCERT.

Ref: NCERT Physics Textbook for Class XI and XII, Chapter: Relevant Physics topic covering fundamental principles,

View Details
PHYSICS

A 4 kg block on a horizontal surface ( μ_k = 0.25 ) is connected to a 2 kg mass over a pulley. A 10 N horizontal force

Given: A 4 kg block on a horizontal surface ( μ_k = 0.25 ) is connected to a 2 kg mass over a pulley. A 10 N horizontal force opposes the motion. What is the acceleration? (Take g = 10 m/s² ) These values define the system as per NCERT data. Formula: For 2 kg : 2g - T = 2a Rightarrow 20 - T = 2a. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: For 4 kg : T - f_k - 10 = 4a, f_k = 0.25 × 4 × 10 = 10 N . T - 10 - 10 = 4a Rightarrow T - 20 = 4a . Solve: 20 - T = 2a, T - 20 = 4a . Substitute T = 20 - 2a into 20 - 2a - 20 = 4a Rightarrow -2a = 4a - 20 . 6a = 20 Rightarrow a = 20/6 approx 3.33 m/s² . Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kg⁻¹ K⁻¹, m/s², 10⁻⁵ are properly used as per NCERT.

Ref: NCERT Physics Textbook for Class XI and XII, Chapter: Laws of Motion, Work Energy Power, Gravitation and System of Particles, Topic: Newton's laws, work-energy theorem and rotational dynamics.

View Details
SI Units and Dimensional Formulae

In motion with constant acceleration in a plane, what is true about the acceleration vector?

The acceleration vector in motion with constant acceleration remains constant in both magnitude and direction. This allows the motion to be analyzed as two independent one-dimensional motions along perpendicular axes. As per NCERT Class 11 Chapter 2, dimensional analysis checks correctness and SI units define base and derived quantities. This principle confirms that It changes magnitude is correct because its dimensions and unit match the physical quantity asked.

Ref: NCERT Class 11 Physics > Chapter 2: Units and Measurements > Topic: SI Units and Dimensional Formulae

View Details