In the Carius method, 0.3 g of a compound gave 0.574 g of AgBr. What is the percentage of bromine?
Molar mass of AgBr = 188 g/mol, Br = 80 g/mol. Mass of Br = (80/188) × 0.574 = 0.244 g. Percentage = (0.244/0.3) × 100 = 81.33%.
Ref: NCERT Class 11 Chemistry > Chapter 8: Organic Chemistry - Some Basic Principles and Techniques > Topic: Qualitative and Quantitative Analysis - Lassaigne Test and Estimation