Practice question
Question
The solubility of AgBr is 7.1 × 10⁻⁷ M . What is its Ksp ?
Explanation
For AgBr <=> Ag+ + Br- , Ksp = [Ag+][Br-] = S² = (7.1 × 10⁻⁷)² = 5.04 × 10⁻¹³ .
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