Practice question

Given: The rate constant of a reaction is 3.0 × 10⁻³ s^{-1 at 25°C and E_a = 62 kJ mol^{-1 . What is the rate constant at 35°C? (R = 8.314 J/mol · K) These values define the system as per NCERT data. Formula: log frack_23.0 × 10⁻³= 62000/2.303 × 8.314 ( 10/298 × 308 ) = 0.352. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: k_2 = 3.0 × 10⁻³ × __10POW₀__.352 = 6.75 × 10⁻³ approx 6.8 × 10⁻³. Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kg⁻¹ K⁻¹, m/s², 10⁻⁵ are properly used as per NCERT.