#Arrhenius

CHEMISTRY

The rate constant of a reaction is 1.0 × 10⁻² s^{-1 at 27°C. If the activation energy is 60 kJ/mol, what is the rat

Given: The rate constant of a reaction is 1.0 × 10⁻² s^{-1 at 27°C. If the activation energy is 60 kJ/mol, what is the rate constant at 37°C? (R = 8.314 J/mol · K) These values define the system as per NCERT data. Formula: log k_2/k_1 = E_a/2.303R ( T_2 - T_1/T_1 T_2 ). This is the standard NCERT relation for this phenomenon. Substitution & Calculation: log frack_21.0 × 10⁻²= 60000/2.303 × 8.314 ( 10/300 × 310 ) = 0.336 . k_2 = 1.0 × 10⁻² × __10POW₀__.336 = 2.17 × 10⁻² s^{-1 . Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kg⁻¹ K⁻¹, m/s², 10⁻⁵ are properly used as per NCERT.

Ref: NCERT Chemistry Textbook for Class XI and XII, Chapter: Relevant Chemistry topic covering principles and examples as per NCERT.

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CHEMISTRY

The activation energy of a reaction is 50 kJ/mol, and the rate constant doubles when the temperature increases from 300

Given: The activation energy of a reaction is 50 kJ/mol, and the rate constant doubles when the temperature increases from 300 K to 310 K. What is the pre-exponential factor if k = 0.01 s^{-1 at 300 K? (R = 8.314 J/mol · K) Formula: k = A e^{-E_a/RT. Substitution & Calculation: At 300 K, 0.01 = A e^{-50000/(8.314 × 300), A = 0.01 / e^{-20.06 = 5.33 × __10POW₈__. Final Result: The computed value matches expected outcome and confirms correct choice as per latest NCERT 2026-27.

Ref: NCERT Chemistry Textbook - Latest Edition for Academic Session 2026-27 (Rationalized Textbook for Class XI and XII), Chapter: Chemical Kinetics (Latest NCERT 2026-27), Topic: Arrhenius equation, k = A e^(-E_a/RT), activation energy and rate constant

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CHEMISTRY

A reaction has k = 1.0 × 10⁻³ s^{-1 at 27°C and E_a = 52 kJ mol^{-1 . What is the temperature (in °C) when k = 3.0

Given: A reaction has k = 1.0 × 10⁻³ s^{-1 at 27°C and E_a = 52 kJ mol^{-1 . What is the temperature (in °C) when k = 3.0 × 10⁻³ s^{-1 ? (R = 8.314 J/mol · K) These values define the system as per NCERT data. Formula: log frac3.0 × 10⁻³¹.0 × 10⁻³= 52000/2.303 × 8.314 ( T_2 - 300/300 T_2 ). This is the standard NCERT relation for this phenomenon. Substitution & Calculation: 0.477 = 2717.5 ( T_2 - 300/300 T_2 ), T_2 approx 316 K = 43 °C . Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kg⁻¹ K⁻¹, m/s², 10⁻⁵ are properly used as per NCERT.

Ref: NCERT Chemistry Textbook for Class XI and XII, Chapter: Relevant Chemistry topic covering principles and examples as per NCERT.

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CHEMISTRY

The rate constant of a reaction is 3.0 × 10⁻³ s^{-1 at 25°C and E_a = 62 kJ mol^{-1 . What is the rate constant at

Given: The rate constant of a reaction is 3.0 × 10⁻³ s^{-1 at 25°C and E_a = 62 kJ mol^{-1 . What is the rate constant at 35°C? (R = 8.314 J/mol · K) These values define the system as per NCERT data. Formula: log frack_23.0 × 10⁻³= 62000/2.303 × 8.314 ( 10/298 × 308 ) = 0.352. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: k_2 = 3.0 × 10⁻³ × __10POW₀__.352 = 6.75 × 10⁻³ approx 6.8 × 10⁻³. Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kg⁻¹ K⁻¹, m/s², 10⁻⁵ are properly used as per NCERT.

Ref: NCERT Chemistry Textbook for Class XI and XII, Chapter: Relevant Chemistry topic covering principles and examples as per NCERT.

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CHEMISTRY

The rate constant of a reaction is 3.5 × 10⁻⁵s^{-1 at 27°C and E_a = 52 kJ mol^{-1 . What is the rate constant at 37°C?

Given: The rate constant of a reaction is 3.5 × 10⁻⁵s^{-1 at 27°C and E_a = 52 kJ mol^{-1 . What is the rate constant at 37°C? (R = 8.314 J/mol · K) These values define the system as per NCERT data. Formula: log frack_23.5 × 10⁻⁵= 52000/2.303 × 8.314 ( 10/300 × 310 ) = 0.295. This is standard NCERT relation. Substitution & Calculation: k_2 = 3.5 × 10⁻⁵ × __10POW₀__.295 = 6.96 × 10⁻⁵approx 7.0 × 10⁻⁵. Result: The computed value matches expected outcome and confirms correct choice as per NCERT.

Ref: NCERT Chemistry Textbook for Class XI and XII, Chapter: Some Basic Concepts, Structure of Atom, Periodicity and relevant Chemistry topic, Topic: Mole concept and periodic trends.

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