Practice question

Given: The activation energy of a reaction is 50 kJ/mol, and the rate constant doubles when the temperature increases from 300 K to 310 K. What is the pre-exponential factor if k = 0.01 s^{-1 at 300 K? (R = 8.314 J/mol · K) Formula: k = A e^{-E_a/RT. Substitution & Calculation: At 300 K, 0.01 = A e^{-50000/(8.314 × 300), A = 0.01 / e^{-20.06 = 5.33 × __10POW₈__. Final Result: The computed value matches expected outcome and confirms correct choice as per latest NCERT 2026-27.