Practice question

**Charles' law** V₁/T₁ = V₂/T₂ at constant pressure, volume proportional to absolute temperature (K), Gay-Lussac P₁/T₁ = P₂/T₂ at constant volume, Boyle's law P₁V₁ = P₂V₂ at constant temperature, combined ideal gas law P V = n R T, R=8.314 J/mol·K. For V₁=24 L T₁=300 K T₂=600 K, V₂= V₁ T₂/T₁=48 L, volume doubles when T doubles at constant P. l = (1)/(√(2) n π d²), d² = (1)/(√(2) n π l).d² = (1)/(1.414 × 4.0 × 10²⁵) × 3.14 × 1.2 × 10⁻⁷ = (1)/(2.13 × 10⁻¹⁹) ≈ 4.69 × 10⁻²⁰.d = √(4.69 × 10⁻²⁰) ≈ 2.17 × 10⁻¹⁰ m. Substituting values gives 2.17