Practice question

**Charles' law** V₁/T₁ = V₂/T₂ at constant pressure, volume proportional to absolute temperature (K), Gay-Lussac P₁/T₁ = P₂/T₂ at constant volume, Boyle's law P₁V₁ = P₂V₂ at constant temperature, combined ideal gas law P V = n R T, R=8.314 J/mol·K. For V₁=24 L T₁=300 K T₂=600 K, V₂= V₁ T₂/T₁=48 L, volume doubles when T doubles at constant P. At STP, 22.4 litres = 1 mole.Charles’ law: (V₁)/(T₁) = (V₂)/(T₂), but moles remain constant at constant P.Initial μ = 1 mol, remains 1 mole as V adjusts with T. Substituting values gives 1.0 mol, which matches expected kinetic theory result, confirming mean free path