Practice question
Question
How many grams of CuO are required to produce 8 g of Cu with excess CO? (Molar masses: CuO = 79.5 g/mol, Cu = 64 g/mol)
Explanation
Reaction: CuO + CO → Cu + CO₂. Moles of Cu = 8/64 = 0.125 mol. 1 mol Cu from 1 mol CuO; mass = 0.125 × 79.5 ≈ 9.94 g.
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