How many grams of CuO are required to produce 8 g of Cu with excess CO? (Molar masses: CuO = 79.5 g/mol, Cu = 64 g/mol)
Reaction: CuO + CO → Cu + CO₂. Moles of Cu = 8/64 = 0.125 mol. 1 mol Cu from 1 mol CuO; mass = 0.125 × 79.5 ≈ 9.94 g.
Ref: NCERT Class 11 Chemistry > Chapter 1: Some Basic Concepts of Chemistry > Topic: Importance and Nature of Chemistry and Properties of Matter