Practice question
Question
A weak acid HZ ( Ka = 3.2 × 10⁻⁵ ) is mixed with 0.02 M NaOH in a 3:1 volume ratio (acid:base). If the final [HZ] = 0.06 M , what is the pH?
Explanation
Total volume = 4V, HZ initial = 0.06 × 4V = 0.08 M × 3V , NaOH = 0.02V , [Z-] = (0.02V/4V) = 0.005 M . pH = 4.5 + log (0.005/0.06) = 4.5 - 1.08 = 3.42 .
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