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#pH calculation

62 public questions tagged with this topic.

CHEMISTRY

The K_a of HF is 6.8 × 10⁻⁴. What is the pH of a 0.1 M HF solution?

Given: The K_a of HF is 6.8 × 10⁻⁴. What is the pH of a 0.1 M HF solution? These values define the system as per NCERT data. Formula: K_a = frac[H+][F-][HF] approx x²/0.1, 6.8 × 10⁻⁴= x²/0.1, x² = 6.8 × 10⁻⁵, x approx 8.25 × 10⁻³. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: pH = -log(8.25 × 10⁻³) approx 2.08 . Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kg⁻¹ K⁻¹, m/s², 10⁻⁵ are properly used as per NCERT.

Ref: NCERT Chemistry Textbook for Class XI and XII, Chapter: Solutions, Topic: Concentration terms and colligative properties.

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CHEMISTRY

What is the pH of a 0.001 M Ba(OH)2 solution, assuming complete dissociation?

Given: What is the pH of a 0.001 M Ba(OH)2 solution, assuming complete dissociation? These values define the system as per NCERT data. Formula: [OH-] = 2 × 0.001 = 0.002 M, pOH = -log(0.002) approx 2.7. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: pH = 14 - 2.7 = 11.3 . Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kg⁻¹ K⁻¹, m/s², 10⁻⁵ are properly used as per NCERT.

Ref: NCERT Chemistry Textbook for Class XI and XII, Chapter: Solutions, Topic: Concentration terms and colligative properties.

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CHEMISTRY

What is the pH of a solution with [OH-] = 2.5 × 10⁻² M?

Given: What is the pH of a solution with [OH-] = 2.5 × 10⁻² M? These values define the system as per NCERT data. Formula: pOH = -log(2.5 × 10⁻²) approx 1.6, pH = 14 - 1.6 = 12.4 .. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: Substituting values like 1.2 × 10⁻⁵, 236 J kg⁻¹ K⁻¹, CH₃CH₂NH₂ etc. into the formula and simplifying step by step. Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kg⁻¹ K⁻¹, m/s², 10⁻⁵ are properly used as per NCERT.

Ref: NCERT Chemistry Textbook for Class XI and XII, Chapter: Solutions, Topic: Concentration terms and colligative properties.

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CHEMISTRY

What is the pH of a 0.006 M KOH solution, assuming complete dissociation?

Given: What is the pH of a 0.006 M KOH solution, assuming complete dissociation? These values define the system as per NCERT data. Formula: [OH-] = 0.006 M, pOH = -log(0.006) approx 2.22. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: pH = 14 - 2.22 = 11.78 approx 11.8 . Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kg⁻¹ K⁻¹, m/s², 10⁻⁵ are properly used as per NCERT.

Ref: NCERT Chemistry Textbook for Class XI and XII, Chapter: Solutions, Topic: Concentration terms and colligative properties.

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CHEMISTRY

What is the pH of a 0.003 M NaOH solution, assuming complete dissociation?

Given: What is the pH of a 0.003 M NaOH solution, assuming complete dissociation? These values define the system as per NCERT data. Formula: [OH-] = 0.003 M, pOH = -log(0.003) approx 2.52. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: pH = 14 - 2.52 = 11.48 approx 11.5 . Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kg⁻¹ K⁻¹, m/s², 10⁻⁵ are properly used as per NCERT.

Ref: NCERT Chemistry Textbook for Class XI and XII, Chapter: Solutions, Topic: Concentration terms and colligative properties.

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CHEMISTRY

What is the pH of a 0.004 M Ca(OH)2 solution, assuming complete dissociation?

Given: What is the pH of a 0.004 M Ca(OH)2 solution, assuming complete dissociation? These values define the system as per NCERT data. Formula: [OH-] = 2 × 0.004 = 0.008 M, pOH = -log(0.008) approx 2.1. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: pH = 14 - 2.1 = 11.9 . Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kg⁻¹ K⁻¹, m/s², 10⁻⁵ are properly used as per NCERT.

Ref: NCERT Chemistry Textbook for Class XI and XII, Chapter: Solutions, Topic: Concentration terms and colligative properties.

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CHEMISTRY

The K_a of formic acid ( HCOOH ) is 1.8 × 10⁻⁴. What is the pH of a 0.02 M solution?

Given: The K_a of formic acid ( HCOOH ) is 1.8 × 10⁻⁴. What is the pH of a 0.02 M solution? Formula: K_a = x²/0.02, 1.8 × 10⁻⁴= x²/0.02, x² = 3.6 × 10⁻⁶. Substitution & Calculation: x = √3.6 × 10⁻⁶approx 1.9 × 10⁻³, pH = -log(1.9 × 10⁻³) approx 2.72 . Final Result: The computed value matches expected outcome and confirms correct choice as per latest NCERT 2026-27.

Ref: NCERT Chemistry Textbook - Latest Edition for Academic Session 2026-27 (Rationalized Textbook for Class XI and XII)Topic: Mole concept, atomic structure, chemical formulas like H₂O, CO₂, CH₃CH₂NH₂ and periodic trends.

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CHEMISTRY

The K_a of propanoic acid is 1.32 × 10⁻⁵. What is the pH of a 0.01 M solution?

Given: The K_a of propanoic acid is 1.32 × 10⁻⁵. What is the pH of a 0.01 M solution? These values define the system as per NCERT data. Formula: K_a = x²/0.01, 1.32 × 10⁻⁵= x²/0.01, x² = 1.32 × 10⁻⁷. This is standard NCERT relation. Substitution & Calculation: x = sqrt1.32 × 10⁻⁷approx 3.63 × 10⁻⁴, pH = -log(3.63 × 10⁻⁴) approx 3.44 . Result: The computed value matches expected outcome and confirms correct choice as per NCERT.

Ref: NCERT Chemistry Textbook for Class XI and XII, Chapter: Some Basic Concepts, Structure of Atom, Periodicity and relevant Chemistry topic, Topic: Mole concept and periodic trends.

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Relationship Between Kp Kc and Factors Affecting Equilibrium - Le Chatelier

The Ksp of Mg(OH)2 is 1.8 × 10⁻¹¹ . What is the pH at which [Mg²⁺] = 1.0 × 10⁻⁴ M in a saturated solution?

For Mg(OH)2 Mg²⁺ + 2OH- , Ksp = [Mg²⁺][OH-]² = 1.8 × 10⁻¹¹ , (1.0 × 10⁻⁴)[OH-]² = 1.8 × 10⁻¹¹ , [OH-]² = 1.8 × 10⁻⁷ , [OH-] = 1.34 × 10⁻⁴ , pOH = 3.87 , pH = 14 - 3.87 = 10.13 .

Ref: NCERT Class 11 Chemistry > Chapter 6: Equilibrium > Topic: Relationship Between Kp Kc and Factors Affecting Equilibrium - Le Chatelier

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