Practice question
Question
A weak acid HA ( Ka = 5.0 × 10⁻⁶ ) is mixed with 0.04 M NaOH in a 2:1 volume ratio (acid:base). If the final [HA] = 0.06 M , what is the pH?
Explanation
Total volume = 3V, initial [HA] = 0.09 M , [A-] = (0.04V/3V) = 0.0133 M , pKa = 5.3 , pH = 5.3 + log (0.0133/0.06) = 5.3 - 0.655 = 4.65 .
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