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Practice question

MCQ

Question

A solution of a non-volatile solute in water has a vapor pressure of 23.7 mm Hg at a temperature where pure water’s vapor pressure is 25 mm Hg. If the solution freezes at -0.372°C, what is the molality? ( Kf = 1.86 K kg mol⁻¹ )

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Explanation

Δ Tf = Kf · m . 0.372 = 1.86 · m . m = (0.372/1.86) = 0.2 mol/kg . Cross-check: xsolute = (25 - 23.7/25) = 0.052 , consistent for dilute solution.

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