Directions For Questions Consider the following statements regarding Raoult’s law:(A) Raoult’s law holds true only for i
(A) and(B) only correct as per chemistry principle.
Ref: NCERT Chemistry Class XII — Solutions
48 public questions tagged with this topic.
(A) and(B) only correct as per chemistry principle.
Ref: NCERT Chemistry Class XII — Solutions
The presence of solute particles and is proportional to solute concentration correct as per chemistry principle.
Ref: NCERT Chemistry Class XII — Solutions
It decreases the vapor pressure correct as per chemistry principle.
Ref: NCERT Chemistry Class XII — Solutions
To decrease the freezing point of water. correct as per chemistry principle.
Ref: NCERT Chemistry Class XII — Solutions
They are both linearly proportional. correct as per chemistry principle.
Ref: NCERT Chemistry Class XII — Solutions
Weak electrolytes do not dissociate completely. correct as per chemistry principle.
Ref: NCERT Chemistry Class XII — Solutions
Depression freezing point colligative depends number particles.
Ref: NCERT Chemistry Class XII — Solutions
Given: In a closed container, water is in equilibrium with its vapor at 25°C, and the vapor pressure is 0.0313 atm. If the volume of the container is doubled suddenly, what happens to the vapor pressure initially? These values define the system as per NCERT data. Formula: Initially, the number of vapor molecules remains the same, but the volume doubles, reducing the pressure to half: 0.0313 / 2 = 0.01565 approx 0.0157 atm.. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: Substituting values like 1.2 × 10â»âµ, 236 J kgâ»Â¹ Kâ»Â¹, CH₃CHâ‚‚N
Ref: NCERT Chemistry Textbook for Class XI and XII, Chapter: Some Basic Concepts, Structure of Atom and Periodicity, Topic: Mole concept, atomic models and periodic trends.
Mole fraction of water = (0.9/0.9 + 0.1) = 0.9 . Vapor pressure = 25 × 0.9 = 22.5 mm Hg .
Ref: NCERT Class 12 Chemistry > Chapter 1: Solutions > Topic: Vapour Pressure and Raoult's Law - Ideal and Non-ideal Solutions
Relative lowering = (p⁰ - p/p⁰) = xsolute . (20 - 19.8/20) = (0.2/20) = 0.01 .
Ref: NCERT Class 12 Chemistry > Chapter 1: Solutions > Topic: Vapour Pressure and Raoult's Law - Ideal and Non-ideal Solutions
(p⁰ - p/p⁰) = xsolute . (25 - 23/25) = 0.08 . Moles of water = (180/18) = 10 . xsolute = (nsolute/nsolute + 10) = 0.08 . nsolute = 0.08 (nsolute + 10) , nsolute - 0.08 nsolute = 0.8 , 0.92 nsolute = 0.8 , nsolute ≈ 0.8696 . Mass = 0.8696 × 60 ≈ 52.18 g .
Ref: NCERT Class 12 Chemistry > Chapter 1: Solutions > Topic: Vapour Pressure and Raoult's Law - Ideal and Non-ideal Solutions
Mole fraction of water = 1 - 0.1 = 0.9 . Vapor pressure = 50 × 0.9 = 45 mm Hg .
Ref: NCERT Class 12 Chemistry > Chapter 1: Solutions > Topic: Vapour Pressure and Raoult's Law - Ideal and Non-ideal Solutions
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