Practice question
Question
A solution of a non-volatile solute in water has a vapor pressure of 23.5 mm Hg at a temperature where pure water’s vapor pressure is 25 mm Hg. If the solution’s boiling point is 100.26°C at 1 atm, what is the molality? ( Kb = 0.52 K kg mol⁻¹ )
Explanation
Δ Tb = 100.26 - 100 = 0.26 K . Δ Tb = Kb · m . 0.26 = 0.52 · m , m = 0.5 mol/kg . Cross-check: xsolute = (25 - 23.5/25) = 0.06 , but vapor pressure not needed here.
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