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Practice question

MCQ

Question

A solution of a non-volatile solute in water has a vapor pressure of 22.4 mm Hg at a temperature where pure water’s vapor pressure is 24 mm Hg. If the solution boils at 100.208°C at 1 atm, what is the molality? ( Kb = 0.52 K kg mol⁻¹ )

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Explanation

Δ Tb = 100.208 - 100 = 0.208 K . Δ Tb = Kb · m . 0.208 = 0.52 · m , m = (0.208/0.52) = 0.4 mol/kg . Cross-check: xsolute = (24 - 22.4/24) = 0.0667 , consistent for dilute solution.

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