Practice question
Question
A solution is prepared by mixing 50 g of a solute with 150 g of water. If the solute’s mass percentage in a second solution (made with the same solute and water) is 40%, what mass of water is required for the second solution?
Explanation
Mass % = (Mass of solute/Total mass) × 100 . For 40%: 40 = (50/50 + w) × 100 . 0.4 (50 + w) = 50 , 50 + w = 125 , w = 75 g .
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