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Mass of sugar = (20/100) × 150 = 30 g . Mass of water = 150 - 30 = 120 g .
Ref: NCERT Class 12 Chemistry > Chapter 1: Solutions > Topic: Solubility - of Solids and Gases in Liquids Henry's Law
Mass % = (Mass of solute/Total mass) × 100 . For 40%: 40 = (50/50 + w) × 100 . 0.4 (50 + w) = 50 , 50 + w = 125 , w = 75 g .
Ref: NCERT Class 12 Chemistry > Chapter 1: Solutions > Topic: Solubility - of Solids and Gases in Liquids Henry's Law
Moles = (15/30) = 0.5 . Δ Tb = Kb · m . 0.26 = 0.52 × (0.5/w) , w = (0.5 × 0.52/0.26) = 1 kg = 1000 g .
Ref: NCERT Class 12 Chemistry > Chapter 1: Solutions > Topic: Colligative Properties - Depression of Freezing Point
Mass of solute = (15/100) × 400 = 60 g . Mass of water = 400 - 60 = 340 g .
Ref: NCERT Class 12 Chemistry > Chapter 1: Solutions > Topic: Colligative Properties - Depression of Freezing Point
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