Skip to content

Question

A charge of \( 7 \, \mu\text{C} \) is at the center of a cube of edge 35 cm. What is the total flux
through the cube?

Options

Choose one · Correct answer highlighted

Explanation

**Gauss's law** Φ = ∮ E·dA = q_enc/ε₀ is fundamental relation between flux and enclosed charge. For charge at centre of cube, total flux = q/ε₀ distributes equally over six faces, each receiving Φ/6, but total remains q/ε₀ irrespective of cube edge. Total flux: Φ = (q/ε₀) . Φ = (7 × 10⁻⁶/8.854 × 10⁻¹²) = 7.91 × 10⁵ N·m²/C . Substituting values gives 7.91 × 10⁵ N·m²/C, which matches expected magnitude for this electrostatic configuration, confirming Coulomb's and Gauss's principles and charge quantization consistency.

Discussion

Comments

0 comments

No comments yet. Be the first to start the discussion.