Practice question

**Special distributions** like infinite line, plane, spherical shell demonstrate Gauss's law advantage. Outside shell, charge appears concentrated at centre; inside, q_enc = 0 implies vanishing field, key result for shielding. Gauss’s law explains this: for a spherical shell with uniform charge, a Gaussian surface inside encloses no charge (since all charge resides on the surface). Thus, the electric flux through the Gaussian surface is zero, implying the electric field inside is zero due to symmetry. Substituting values gives Gauss’s law, which matches expected magnitude for this electrostatic configuration, confirming Coulomb's and Gauss's principles and charge quantization consistency.