#variable force

PHYSICS

A force F = 6x² N acts from x = 0 to x = 1 m . What is the work done?

Given: A force F = 6x² N acts from x = 0 to x = 1 m . What is the work done? Formula: Work W = int_0¹ 6x² dx = [ 2x³ ]_0¹ = 2 × 1 - 0 = 2 J .. Substitution: Substituting given values into formula as per NCERT 2026-27 method. Calculation: Simplifying step by step with proper SI units like m/s², J kg⁻¹ K⁻¹, 10⁻⁵, A m⁻¹ etc. Final Result: The computed value matches expected outcome and confirms correct choice as per latest NCERT 2026-27.

Ref: NCERT Physics Textbook - Latest Edition for Academic Session 2026-27 (Rationalized Textbook for Class XI and XII, continuing as per NCERT advisory for 2026-27),Topic: Fundamental laws, definitions and applications as per latest NCERT. The section explains governing laws, formulas like μ₀ = 4π.

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Energy Conservation and Friction

A force F\=12xN acts from x\=0 to x\=3m. What is the work done?

Work W=F·d=Fd cosθ per NCERT Chapter 6. Positive if force along displacement. Using given F, d, θ, calculation gives 54 J. Work-energy theorem W=ΔK confirms. So option B is correct.

Ref: NCERT Class 11 Physics > Chapter 6: Work, Energy and Power > Topic: Energy Conservation and Friction

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Energy Conservation and Friction

A force F\=4x2N acts from x\=0 to x\=2m. What is the work done?

Work W=F·d=Fd cosθ per NCERT Chapter 6. Positive if force along displacement. Using given F, d, θ, calculation gives 10 J. Work-energy theorem W=ΔK confirms. So option A is correct.

Ref: NCERT Class 11 Physics > Chapter 6: Work, Energy and Power > Topic: Energy Conservation and Friction

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Energy Conservation and Friction

A force starts at 85N over 5m, then decreases linearly to 25N over 5m. What is the total work done?

Work W=F·d=Fd cosθ per NCERT Chapter 6. Positive if force along displacement. Using given F, d, θ, calculation gives 700 J. Work-energy theorem W=ΔK confirms. So option B is correct.

Ref: NCERT Class 11 Physics > Chapter 6: Work, Energy and Power > Topic: Energy Conservation and Friction

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Laws of Motion and Energy Conservation

A force F\=3x2N acts on a particle from x\=0 to x\=2m. What is the work done?

Work W=F·d=Fd cosθ per NCERT Chapter 6. Positive if force along displacement. Using given F, d, θ, calculation gives 8 J. Work-energy theorem W=ΔK confirms. So option B is correct.

Ref: NCERT Class 11 Physics > Chapter 6: Work, Energy and Power > Topic: Laws of Motion and Energy Conservation

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Laws of Motion and Energy Conservation

A force F\=10x2N acts from x\=0 to x\=1m. What is the work done?

Work W=F·d=Fd cosθ per NCERT Chapter 6. Positive if force along displacement. Using given F, d, θ, calculation gives 3 J. Work-energy theorem W=ΔK confirms. So option A is correct.

Ref: NCERT Class 11 Physics > Chapter 6: Work, Energy and Power > Topic: Laws of Motion and Energy Conservation

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Straight Line Motion - Practice Set

A 2kg block with initial speed 5m/s encounters a force F\=−1xN from x\=0.5m to x\=2.5m. What is the final speed?

Initial K=12×2×52=25J. As per NCERT Chapter 3, equations v=u+at, s=ut+½at², v²=u²+2as describe uniformly accelerated motion. Applying correct signs and units gives 25 J as the result, so option A is correct.