Practice question
Question
A force F\=3x2N acts on a particle from x\=0 to x\=2m. What is the work done?
Explanation
Work W=F·d=Fd cosθ per NCERT Chapter 6. Positive if force along displacement. Using given F, d, θ, calculation gives 8 J. Work-energy theorem W=ΔK confirms. So option B is correct.