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At bottom: Tb−mg=mvb2/r⇒20−0.4×10=0.4×vb2/2. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 0.4. This satisfies dimensional consistency and physical conditions given, so option A is scientifically correct.
Ref: NCERT Class 11 Physics > Chapter 6: Work, Energy and Power > Topic: Work, Energy and Power - Work-Energy Theorem
At bottom: Tb−mg=mvb2/r⇒Tb−1×10=1×(20)2/4. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 90 N. This satisfies dimensional consistency and physical conditions given, so option A is scientifically correct.
Ref: NCERT Class 11 Physics > Chapter 6: Work, Energy and Power > Topic: Work, Energy and Power - Work-Energy Theorem
Angular speed: ω=50×2π60=5π3rad/s. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 10 N. This satisfies dimensional consistency and physical conditions given, so option A is scientifically correct.
Ref: NCERT Class 11 Physics > Chapter 6: Work, Energy and Power > Topic: Work, Energy and Power - Work-Energy Theorem
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