Practice question
Question
A 1kg stone in a vertical circle of radius 4m has a speed of 20m/s at the bottom. A tangential force of 4N acts downward from bottom to top. What is the tension at the top? (Take g\=10m/s2)
Explanation
At bottom: Tb−mg=mvb2/r⇒Tb−1×10=1×(20)2/4. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 90 N. This satisfies dimensional consistency and physical conditions given, so option A is scientifically correct.
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