Practice question
Question
A 0.2kg ball is dropped from 12m. What is its speed just before hitting the ground? (Take g\=10m/s2)
Explanation
Potential energy V=mgh=0.2×10×12=24J. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 14 m/s. This satisfies dimensional consistency and physical conditions given, so option A is scientifically correct.
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