12 public questions tagged with this topic.
Stokes’ law: F = 6πηav. η = 1.0×10−3Pa s, a = 0.015m, v = 0.2m/s. F = 6×3.14×1.0×10−3×0.015×0.2 = 5.652×10−5N. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 5.65 × 10⁻⁵ N. This satisfies dimensional consistency and physical conditions given, so option C is scientifically correct.
Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.
Stokes’ law: F = 6πηav. η = 2.7×10−3Pa s, a = 0.025m, v = 0.08m/s. F = 6×3.14×2.7×10−3×0.025×0.08 = 1.017×10−4N. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 1.0 × 10⁻⁴ N. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.
Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.
Stokes’ law: F = 6πηav. η = 0.2Pa s, a = 0.04m, v = 0.12m/s. F = 6×3.14×0.2×0.04×0.12 = 0.1809N. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 0.18 N. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.
Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.
Stokes’ law: F = 6πηav. η = 0.113Pa s, a = 0.03m, v = 0.15m/s. F = 6×3.14×0.113×0.03×0.15 = 0.0958N. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 0.096 N. This satisfies dimensional consistency and physical conditions given, so option C is scientifically correct.
Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.
Stokes’ law: F = 6πηav. η = 0.83Pa s, a = 0.035m, v = 0.09m/s. F = 6×3.14×0.83×0.035×0.09 = 0.0493N. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 0.05 N. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.
Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.
Stokes’ law: F = 6πηav. η = 0.034Pa s, a = 0.045m, v = 0.15m/s. F = 6×3.14×0.034×0.045×0.15 = 0.0433N. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 0.043 N. This satisfies dimensional consistency and physical conditions given, so option C is scientifically correct.
Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.
Using Stokes’ law: F = 6πηav. η = 0.83Pa s, a = 0.02m, v = 0.1m/s. F = 6×3.14×0.83×0.02×0.1≈0.0313N. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 0.031 N. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.
Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.
Stokes’ law: F = 6πηav. η = 0.83Pa s, a = 0.06m, v = 0.13m/s. F = 6×3.14×0.83×0.06×0.13 = 0.1222N. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 0.12 N. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.
Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.
Stokes’ law (F = 6πηav) shows that viscous force is proportional to radius (a), while weight (43πa3ρg) depends on a3. At terminal velocity, these balance, making v∝a2. As per NCERT, applying relevant law/formula with correct units and sign convention leads to Viscous force depends on radius. This satisfies dimensional consistency and physical conditions given, so option C is scientifically correct.
Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.
Stokes’ law: F = 6πηav. η = 0.2Pa s, a = 0.07m, v = 0.14m/s. F = 6×3.14×0.2×0.07×0.14 = 0.0369N. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 0.036 N. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.
Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.
