Viscous drag force on a sphere in glycerine

Practice question

Question

A sphere of radius 0.035m moves at 0.09m/s through glycerine (η\=0.83Pa s). What is the viscous drag force?

Options

Choose one · Correct answer highlighted

0.04 N 0.05 N Correct 0.06 N 0.07 N

Explanation

Stokes’ law: F = 6πηav. η = 0.83Pa s, a = 0.035m, v = 0.09m/s. F = 6×3.14×0.83×0.035×0.09 = 0.0493N. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 0.05 N. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.

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