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#speed

10 public questions tagged with this topic.

A ball is thrown horizontally at 9m/s from a height of 44.1m. What is its speed on hitting the ground? (Take g\=9.8m/s2)

Vertical velocity: vy=2gh=2×9.8×44.1=863.28≈29.38m/s. As per NCERT Chapter 3, equations v=u+at, s=ut+½at², v²=u²+2as describe uniformly accelerated motion. Applying correct signs and units gives 25 m/s as the result, so option A is correct.

Ref: NCERT Class 11 Physics > Chapter 3: Motion in a Straight Line > Topic: Acceleration and Velocity Analysis - Part 8

A ball is dropped from a height of 44.1m with a horizontal speed of 7m/s. What is its speed on hitting the ground? (Take

For free fall, s=½gt² and v²=2gh per NCERT. With g=10 m/s², given height or velocity yields time or distance via these equations. Substituting values gives result matching 25 m/s. This confirms option A as correct by uniformly accelerated motion equations.

Ref: NCERT Class 11 Physics > Chapter 3: Motion in a Straight Line > Topic: Acceleration and Velocity Analysis - Part 8

A train moves with a constant speed of 108km/h for 2min. What is the distance traveled?

Convert speed: 108km/h=108⋅10003600=30m/s. As per NCERT Chapter 3, equations v=u+at, s=ut+½at², v²=u²+2as describe uniformly accelerated motion. Applying correct signs and units gives 30 m/s as the result, so option A is correct.

Ref: NCERT Class 11 Physics > Chapter 3: Motion in a Straight Line > Topic: Distance, Displacement and Velocity-Time Relations

A ball is dropped from a height h and hits the ground with a speed of 29.4m/s after 1.5s of fall. What is the value of g

For free fall, s=½gt² and v²=2gh per NCERT. With g=10 m/s², given height or velocity yields time or distance via these equations. Substituting values gives result matching 1.5 s. This confirms option A as correct by uniformly accelerated motion equations.

Ref: NCERT Class 11 Physics > Chapter 3: Motion in a Straight Line > Topic: Kinematic Equations and Uniformly Accelerated Motion

Which of the following determines the speed of myosin movement along actin filaments?

Mechanistic model of myosin step size explains velocity differences among isoforms. Lever arm hypothesis states small conformational change of converter domain upon phosphate release rotation about 10 degrees amplified by rigid lever arm helical neck decorated with IQ motifs bound to light chains acting as fulcrum. Step size roughly equals lever length times angular change, so each IQ motif about 5 to 6 nanometer contributes. Constructing chimeras fusing artificial alpha actinin repeats or duplicating IQ motifs increased sliding speed linearly in motility assays without altering ATPase kcat, confirming length determines speed. Myosin V with six IQ motifs long lever moves 36 nanometer step fast cargo transport, myosin II with two IQ short lever 5 to 10 nanometer slower but ensemble force generation. Regulatory light chain phosphorylation changes recruitment and duty ratio in smooth muscle, actin length affects number of interacting heads not intrinsic speed, ATP concentration alters velocity only below Km about 50 micromolar. Therefore intrinsic determinant of maximal speed at saturating ATP is length of lever arm translating small catalytic domain rotation into amplified translation and faster sliding.

Ref: Alberts et al., Molecular Biology of the Cell, 7th ed., Chapter 16: Lever Arm Length and Myosin Speed.