Practice question
Question
A ball is thrown horizontally at 9m/s from a height of 44.1m. What is its speed on hitting the ground? (Take g\=9.8m/s2)
Explanation
Vertical velocity: vy=2gh=2×9.8×44.1=863.28≈29.38m/s. As per NCERT Chapter 3, equations v=u+at, s=ut+½at², v²=u²+2as describe uniformly accelerated motion. Applying correct signs and units gives 25 m/s as the result, so option A is correct.