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Oxidation: 10Cl− → 5Cl₂ + 10e−. Reduction: 2MnO₄− + 10e− → 2Mn₂+. Total electrons = 10.
Ref: NCERT Class 11 Chemistry > Chapter 7: Redox Reactions > Topic: Redox Titrations and Equivalent Weight and Normality
The oxidizing agent accepts electrons. Cl₂ (0) gains electrons to become Cl− (-1), oxidizing Na.
Ref: NCERT Class 11 Chemistry > Chapter 7: Redox Reactions > Topic: Applications of Redox Reactions and Disproportionation
Moles of NaCl = 0.1 mol. Moles of H₂O = 5 mol. Total moles = 5.1; mole fraction = 0.1/5.1 ≈ 0.0196.
Ref: NCERT Class 11 Chemistry > Chapter 1: Some Basic Concepts of Chemistry > Topic: Concentration Terms - Molarity Molality and Mole Fraction
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