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Question

In the reaction 2KMnO₄ + 16H₂SO₄ + 10NaCl → 5Cl₂ + 2MnSO₄ + 8H₂O + 5Na₂SO₄ + K₂SO₄, how many electrons are transferred?

Options

Choose one · Correct answer highlighted

Explanation

Oxidation: 10Cl− → 5Cl₂ + 10e−. Reduction: 2MnO₄− + 10e− → 2Mn₂+. Total electrons = 10.

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