What is the oxidation number of sulfur in SO₃?
Let S = x. O = -2. Equation: x + 3(-2) = 0, x - 6 = 0, x = +6.
Ref: NCERT Class 11 Chemistry > Chapter 7: Redox Reactions > Topic: Classical and Electronic Concept of Redox and Oxidation Number
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For 2SO₂(g) + O₂(g) 2SO₃(g) , Kp = 100 at 800 K. If initial pressures are PSO₂ = 1 atm , PO₂ = 0.5 atm , what is PSO₃ at
Let PSO₃ = 2x , PSO₂ = 1 - 2x , PO₂ = 0.5 - x . Kp = ((PSO₃)²/PSO₂² PO₂) = ((2x)²/(1 - 2x)² (0.5 - x)) = 100 , (4x²/(1 - 2x)² (0.5 - x)) = 100 , (2x/1 - 2x) · (1/sqrt0.5 - x) = 10 , x ≈ 0.45 , PSO₃ = 0.9 atm .
Ref: NCERT Class 11 Chemistry > Chapter 6: Equilibrium > Topic: Physical Equilibrium - Solid-Liquid Gas-Liquid and Henry's Law
The hybridization of sulfur in SO₃ is:
In SO₃ , sulfur has 3 double bonds (3 bonding domains), requiring sp² hybridization for a trigonal planar shape.
Ref: NCERT Class 11 Chemistry > Chapter 4: Chemical Bonding and Molecular Structure > Topic: Valence Bond Theory and Hybridisation - sp sp2 sp3 dsp2
