Practice question
Question
For 2SO₂(g) + O₂(g) <=> 2SO₃(g) , Kp = 100 at 800 K. If initial pressures are PSO₂ = 1 atm , PO₂ = 0.5 atm , what is PSO₃ at equilibrium?
Explanation
Let PSO₃ = 2x , PSO₂ = 1 - 2x , PO₂ = 0.5 - x . Kp = ((PSO₃)²/PSO₂² PO₂) = ((2x)²/(1 - 2x)² (0.5 - x)) = 100 , (4x²/(1 - 2x)² (0.5 - x)) = 100 , (2x/1 - 2x) · (1/sqrt0.5 - x) = 10 , x ≈ 0.45 , PSO₃ = 0.9 atm .
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