Two lls of emf 4 V and 6 V with internal resistances 1 Ω and 2 Ω respectively are connected in series. What is the equiv
Given: Two lls of emf 4 V and 6 V with internal resistances 1 Ω and 2 Ω respectively are connected in series. What is the equivalent emf and internal resistance of the combination? These values define the system as per NCERT data. Formula: For series: varepsilon_{eq = varepsilon_1 + varepsilon_2 = 4 + 6 = 10 V. This is standard NCERT relation. Substitution & Calculation: Internal resistance: r_{eq = r_1 + r_2 = 1 + 2 = 3 Ω . Result: The computed value matches expected outcome and confirms correct choice as per NCERT.
Ref: NCERT Physics Textbook for Class XI and XII, Chapter: Electrostatic Potential and Capacitance, Topic: Capacitors in series, equivalent capacitance 1/C_eq = 1/C₁ + 1/C₂. The section explains definitions, governing laws, formulas like μ₀ = 4π × 10⁻⁷ T·m/A, units and illustrative examples.